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Unit 19: Alternating Currents

Physics - Class 12

This chapter explores alternating current (AC) fundamentals, including peak and RMS values, behavior of AC through resistive, inductive, and capacitive elements, phasor representation, series RLC circuits, resonance, quality factor, and power calculations. Detailed definitions, formulas, and illustrative examples are provided to build a strong conceptual and mathematical foundation for Class 12 Physics.

No MCQ questions available for this chapter.

Unit 19: Alternating Currents

1. Peak and RMS Values

In alternating current circuits, the instantaneous voltage or current varies sinusoidally with time. Two important measures are used:

  • Peak value (V₀ or I₀): Maximum magnitude attained during a cycle.
  • RMS value (Vrms or Irms): Root‑mean‑square (effective) value that produces the same heating effect as a DC of equal magnitude.

For a pure sinusoid:

V_rms = V₀ / √2

I_rms = I₀ / √2

Power in AC circuits is calculated using RMS values:

P = V_rms × I_rms × cos φ

where φ is the phase angle between voltage and current.

AC Through \ R, \ L, \ C \> < /h3> < p>When an AC source is connected to a single passive element, the voltage and current exhibit specific phase relationships: < /p> < ul> < li> < strong>Resistor (R): < /strong> Voltage and current are in phase. Ohm’s law holds instantaneously: V(t) = I(t) R. In phasor form: V̂ = Î R. < /li> < li> < strong>Inductor (L): < /strong> The current lags the voltage by 90° (π/2 rad). Inductive reactance: X_L = ωL, where ω = 2πf. Phasor relation: V̂ = Î jX_L. < /li> < li> < strong>Capacitor (C): < /strong> The current leads the voltage by 90°. Capacitive reactance: X_C = 1/(ωC). Phasor relation: V̂ = Î (-jX_C). < /li> < /ul> < p>These relationships can be visualized using phasor diagrams, where each sinusoidal quantity is represented by a rotating vector (phasor) whose length equals the RMS value and whose angle represents the phase. < /p> < h2>2. Phasor Diagram < /h2> < p>A phasor is a complex number  = A ∠θ that encodes both magnitude (A) and phase (θ) of a sinusoidal quantity a(t) = A√2 cos(ωt + θ). In AC analysis: < /p> < ul> < li>The real part of the phasor corresponds to the instantaneous value at t = 0. < /li> < li>Phasors rotate counter‑clockwise at angular speed ω; however, for steady‑state analysis we consider them stationary, capturing only the relative phase. < /li> < li>Adding or subtracting phasors follows vector addition/subtraction rules, simplifying circuit equations. < /li> < /ul> < p>Example: For a series RL circuit, the voltage phasor is the vector sum of ÎR (in phase with current) and ÎjX_L (leading current by 90°). The resultant phasor gives the total voltage magnitude and its phase relative to the current. < /p> < h2>3. Series RLC Circuit < /h2> < p>When a resistor, inductor, and capacitor are connected in series with an AC source, the same current flows through each element. The total opposition to current is called impedance (Z). < /p> < h3>Impedance and Phase Angle < /h3> < p>The inductive and capacitive reactances oppose each other. Net reactance: X = X_L – X_C. Impedance magnitude: Z = √[R² + (X_L – X_C)²]. < /p> < p>Phase angle φ between source voltage and current: tan φ = (X_L – X_C)/R. < /p> < p>If X_L > X_C, the circuit is inductive (voltage leads current, φ > 0). If X_C > X_L, it is capacitive (voltage lags current, φ < 0). At resonance X_L = X_C, φ = 0 and the circuit behaves purely resistively. < /p> < h3>Phasor Representation < /h3> < p>In the phasor diagram for a series RLC: < /p> < ol> < li>Draw the current phasor along the reference axis (0°). < /li> < li>The voltage across the resistor V̂_R = ÎR lies on the same axis (in phase). < /li> < li>The inductor voltage V̂_L = ÎjX_L leads the current by +90°. < /li> < li>The capacitor voltage V̂_C = Î(-jX_C) lags the current by –90°. < /li> < li>The source voltage V̂ = V̂_R + V̂_L + V̂_C is the vector sum of these three. < /li> < p>The resulting phasor determines the magnitude |V̂| = ÎZ and the phase φ. < /p> < h2>4. Series Resonance and Quality Factor < /h2> < h3>Resonance Condition < /h3> < p>Series resonance occurs when the inductive and capacitive reactances cancel: X_L = X_C. At this frequency the impedance is minimum and purely resistive: Z_min = R. Consequently, the circuit current reaches its maximum value: I_max = V₀ / R. < /p> < h3>Resonant Frequency < /h3> < p>Setting ωL = 1/(ωC) gives the resonant angular frequency: ω₀ = 1/√(LC). In hertz: f₀ = 1/(2π√(LC)). < /p> < h3>Quality Factor (Q) < /h3> < p>The quality factor measures the sharpness of the resonance peak: Q = ω₀L / R = 1/(ω₀CR). A high Q indicates a narrow bandwidth and high selectivity. Bandwidth (Δf) is related by: Δf = f₀ / Q. < /p> < p>Energy perspective: Q also equals the ratio of energy stored in the reactive elements to the energy dissipated per radian in the resistor. < /p> < h2>5. Power in AC Circuits < /h2> < h3>Instantaneous and Average Power < /h3> < p>Instantaneous power: p(t) = v(t) i(t). For sinusoidal quantities, the average (real) power over a cycle is: P = V_rms I_rms cos φ, where cos φ is the power factor. < /p> < h3>Power Factor < /h3> < p>Power factor = cos φ = R / Z. It indicates the fraction of apparent power (S = V_rms I_rms) that is converted into useful work. < /p> < ul> < li>When φ = 0 (purely resistive), power factor = 1 (unity). < /li> < li>When φ = ±90° (purely reactive), power factor = 0 (no real power). < /li> < h3>Power at Resonance < /h3> < p>At series resonance, X_L = X_C ⇒ Z = R ⇒ φ = 0 ⇒ cos φ = 1. Hence, the power factor is unity and the average power delivered to the circuit is maximized: P_max = V_rms² / R. < /p> < h2>6. Illustrative Examples < /h2> < h3>Example 1: RMS Calculation < /h3> < p>A sinusoidal voltage has a peak value of 300 V. Compute its RMS value. < /p> < p>V_rms = 300 V / √2 ≈ 212 V. < /p> < h3>Example 2: Impedance of Series RLC < /h3> < p>Given R = 10 Ω, L = 0.2 H, C = 50 µF, and f = 60 Hz, find Z and φ. < /p>
  1. ω = 2πf = 2π×60 ≈ 377 rad/s.
  2. X_L = ωL = 377×0.2 ≈ 75.4 Ω.
  3. X_C = 1/(ωC) = 1/(377×50×10⁻⁶) ≈ 53.1 Ω.
  4. Net reactance X = X_L – X_C ≈ 22.3 Ω (inductive).
  5. Z = √[R² + X²] = √[10² + (22.3)²] ≈ √[100 + 497] ≈ √597 ≈ 24.4 Ω.
  6. tan φ = X/R = 22.3/10 = 2.23 → φ ≈ arctan(2.23) ≈ 65.6° (voltage leads current).

Example 3: Resonant Frequency and Q < /h3> < p>For L = 0.1 H and C = 10 µF: < /p>
  1. f₀ = 1/(2π√(LC)) = 1/(2π√(0.1×10×10⁻⁶)) ≈ 1/(2π√(1×10⁻⁶)) = 1/(2π×0.001) ≈ 159 Hz.
  2. ω₀ = 2πf₀ ≈ 1000 rad/s.
  3. Q = ω₀L / R. Assuming R = 5 Ω, Q = (1000×0.1)/5 = 20.

Bandwidth Δf = f₀ / Q ≈ 159 Hz / 20 ≈ 8 Hz. < /p>

Summary < /h2>

This chapter has established the core concepts needed to analyse AC circuits: peak and RMS values, phase relationships in R, L, and C elements, phasor techniques for visualising and calculating voltages and currents, impedance and resonance in series RLC circuits, and power calculations including power factor. Mastery of these topics enables the solution of a wide range of problems in alternating‑current theory and prepares students for more advanced studies in electronics and electrical engineering. < /p>